-w^2+100w=0

Solution for -w^2+100w=0 equation:

-w^2+100w=0

We add all the numbers together, and all the variables

-1w^2+100w=0

a = -1; b = 100; c = 0;
Δ = b2-4ac
Δ = 1002-4·(-1)·0
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-100}{2*-1}=\frac{-200}{-2}
=+100
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+100}{2*-1}=\frac{0}{-2}
=0
$